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Power Rating (1): The basics

A project log for Programmable Precision Resistor

A SCPI programmable precision resistor

sebastianSebastian 07/23/2023 at 17:530 Comments

In the last post we worked on some implementation details to consolidate the bill of material while improving the power rating of the decade resistor. However, we didn’t fully analyze the design regarding power dissipation.

A bunch of (power/leaded) resistors with different power ratings 

So let’s do that now and get some definitions out of the way:

nDecade n providing resistance values 0 Ω, 1⋅10n Ω to 2⋅10n Ω
RnTotal resistance of decade n as set by the switches
R0nResistance of an individual resistor of decade n (in the example: R0n = 2 Ω)
P0nPower rating of any individual resistor of decade n @ power rating
Imax,nMaximum allowable current for decade n
Pmax,nMaximum allowable power dissipation for decade n
Umax,nMaximum allowable voltage for decade n
Imax,totMaximum allowable current for the programmable resistor (all decades)
Pmax,totMaximum allowable power dissipation for the programmable resistor (all decades)
Umax,totMaximum allowable voltage for the programmable resistor (all decades)

Note: I don't think that hackaday supports inline LaTeX. Please let me know if it does.

The definitions imply that we use identical resistors throughout a decade. For this post we also assume that the power rating of all resistors are the same. In reality this is not the case. That’s one of the reasons for part 2 of this post…

Exemplary calculation for the first decade

 First decade (n=0)

Let Imax,0 flow into the first decade (n = 0, R00 = 2 Ω) with all switches open except for SW12. The resulting resistance is R0 = 5 Ω = 2.5 R00. Then:

Hence Imax,0 is defined by the current that flows through R13 when the dissipated power equals its power rating:

The maximum total power dissipation of the decade is the sum of the power dissipation of the individual resistors (at their respective current). Accordingly:

The maximum allowable voltage is:

Table for decade n

To generalize the example shown above, here's a table showing the results for all resistance values in tabular form.

R0 / R0nImax,nPmax,nUmax,n
0limited by relayslimited by relayslimited by relays
12 I0n2 P0nsqrt(P0nR0n)
22 I0n4 P0n2 sqrt(P0nR0n)
32 I0n6 P0n3 sqrt(P0nR0n)
4I0n2 P0n2 sqrt(P0nR0n)
5I0n2.5 P0n2.5 sqrt(P0nR0n)
6I0n3 P0n3 sqrt(P0nR0n)
7I0n3.5 P0n3.5 sqrt(P0nR0n)
8I0n4 P0n4 sqrt(P0nR0n)
9I0n4.5 P0n4.5 sqrt(P0nR0n)

Considerations for multi-decade resistors

If the power rating of the individual resistors in the programmable resistor are identical, the maximum current Imax,tot is limited by the decade with the highest resistance. To prove this, we show that the largest maximum permissible current of a higher decade m is still less than the smallest maximum permissible current of a lower decade n < m.

1. Determine the smallest maximum permissible current for the lower decade n

With the total resistance of a decade of Rn = ln ⋅ R0n, the smallest maximum current for decade n results for ln > 3 (see table for sigle decade). Therefore:

2. Determine the largest maximum permissible current for the higher decade m

With the total resistance of a decade of Rm = lmR0m, the largest maximum current for decade m results for lm in {1, 2, 3} (see table for sigle decade). Therefore:

3. Utilize the assumptions

If m is the next-higher decade (i. e. m = n + 1), the resistor value for decade m is ten times larger than for decade n

Also, we assumed that the power ratings of all resistors all equal:

4. Bringing it all together

Therefore, under these assumptions the power rating of the programmable resistor is limited by the highest non-zero decade.

Conclusion and next steps

The main take-aways are:

The next post in this series will focus on the actual component selection and the implications on the subject of the power rating of the programmable decade resistor.

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